Math Problem Statement
derivative of x^y=y^x
Solution
To find the derivative of the equation , we can proceed with implicit differentiation. Here's the step-by-step approach:
Step 1: Take the natural logarithm of both sides
First, take the natural logarithm of both sides to simplify the equation:
Using the logarithmic identity , this becomes:
Step 2: Differentiate implicitly
Now, differentiate both sides with respect to , keeping in mind that is a function of (i.e., ).
- Left side: Use the product rule to differentiate .
- Right side: Use the product rule to differentiate .
Step 3: Set up the equation
Now, equate the derivatives from both sides:
Step 4: Solve for
Move the terms involving to one side:
Factor out on the left-hand side:
Now solve for :
Final Answer:
The derivative of the equation with respect to is:
Let me know if you want further clarification or details on any part!
Related Questions:
- How can we apply implicit differentiation to equations involving both and ?
- What are some special cases for the equation when ?
- How would you solve for explicitly if possible?
- What is the geometric interpretation of this equation and its derivative?
- How does the derivative behave when and approach certain values?
Tip: When differentiating equations like , taking the logarithm of both sides often simplifies the process significantly!
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Math Problem Analysis
Mathematical Concepts
Implicit Differentiation
Exponential Functions
Logarithms
Formulas
ln(a^b) = b * ln(a)
Product Rule: d/dx (u*v) = u' * v + u * v'
dy/dx = (ln(y) - (y/x)) / (ln(x) - (x/y))
Theorems
Implicit Differentiation Theorem
Logarithmic Properties
Suitable Grade Level
Grades 11-12